{"id":1372,"date":"2026-05-12T21:47:41","date_gmt":"2026-05-12T21:47:41","guid":{"rendered":"https:\/\/books.gw-project.org\/basic-hydrogeology-an-introduction-to-the-fundamentals-of-groundwater-science\/chapter\/exercise-22\/"},"modified":"2026-05-13T03:35:45","modified_gmt":"2026-05-13T03:35:45","slug":"exercise-22","status":"publish","type":"chapter","link":"https:\/\/books.gw-project.org\/basic-hydrogeology-an-introduction-to-the-fundamentals-of-groundwater-science\/chapter\/exercise-22\/","title":{"raw":"Exercise 22","rendered":"Exercise 22"},"content":{"raw":"
\r\n
\r\n
Calculate molarity and milliequivalents, then determine the charge balance for the following sample. The atomic weight and valance charge for each ion are provided in the table. State if the charge balance is acceptable or not. If the charge balance is not acceptable, state if the cations or the anions are in excess of the balance.<\/blockquote>\r\n<\/div>\r\n<\/colgroup>\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n
A<\/strong><\/td>\r\nB<\/strong><\/td>\r\nC<\/strong><\/td>\r\nD<\/strong><\/td>\r\nE<\/strong><\/td>\r\nF<\/strong><\/td>\r\n<\/tr>\r\n
Solute<\/strong><\/td>\r\nMeasured Concentration (mg\/L)<\/strong><\/td>\r\nAtomic weight(g)<\/strong><\/td>\r\nMolarity (mmol\/L)<\/strong><\/td>\r\nValence (charge)<\/strong><\/td>\r\nmeq\/L<\/strong><\/td>\r\n<\/tr>\r\n
[latex]{Ca}_{}^{2 +}[\/latex]<\/td>\r\n75<\/td>\r\n40.08<\/td>\r\n<\/td>\r\n2<\/td>\r\n<\/td>\r\n<\/tr>\r\n
[latex]{Mg}_{}^{2 +}[\/latex]<\/td>\r\n25<\/td>\r\n24.31<\/td>\r\n<\/td>\r\n2<\/td>\r\n<\/td>\r\n<\/tr>\r\n
[latex]{Na}_{}^{+}[\/latex]<\/td>\r\n5.6<\/td>\r\n23<\/td>\r\n<\/td>\r\n1<\/td>\r\n<\/td>\r\n<\/tr>\r\n
[latex]K_{}^{+}[\/latex]<\/td>\r\n2.1<\/td>\r\n39.1<\/td>\r\n<\/td>\r\n1<\/td>\r\n<\/td>\r\n<\/tr>\r\n
[latex]{Fe(III)}_{}^{}[\/latex]<\/td>\r\n0.2<\/td>\r\n55.8<\/td>\r\n<\/td>\r\n3<\/td>\r\n<\/td>\r\n<\/tr>\r\n
[latex]{HCO}_{3}^{-}[\/latex]<\/td>\r\n109<\/td>\r\n61<\/td>\r\n<\/td>\r\n1<\/td>\r\n<\/td>\r\n<\/tr>\r\n
[latex]{SO}_{4}^{2 -}[\/latex]<\/td>\r\n242<\/td>\r\n96<\/td>\r\n<\/td>\r\n2<\/td>\r\n<\/td>\r\n<\/tr>\r\n
[latex]{Cl}_{}^{-}[\/latex]<\/td>\r\n9.3<\/td>\r\n35.5<\/td>\r\n<\/td>\r\n1<\/td>\r\n<\/td>\r\n<\/tr>\r\n
[latex]{NO}_{3}^{-}[\/latex]<\/td>\r\n15<\/td>\r\n62<\/td>\r\n<\/td>\r\n1<\/td>\r\n<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n
\r\n\r\nSolution for Exercise 22<\/strong><\/span><\/a>\u2ba7\r\n\r\n<\/div>\r\n
\r\n\r\nReturn to where text linked to Exercise 22<\/strong><\/span><\/a>\u2ba5\r\n\r\n<\/div>\r\n<\/div>","rendered":"
\n
\n

Calculate molarity and milliequivalents, then determine the charge balance for the following sample. The atomic weight and valance charge for each ion are provided in the table. State if the charge balance is acceptable or not. If the charge balance is not acceptable, state if the cations or the anions are in excess of the balance.<\/p><\/blockquote>\n<\/div>\n\n\n\n\n\n\n\n<\/colgroup>\n\n\n\n\n\n\n\n\n\n\n\n\n
A<\/strong><\/td>\nB<\/strong><\/td>\nC<\/strong><\/td>\nD<\/strong><\/td>\nE<\/strong><\/td>\nF<\/strong><\/td>\n<\/tr>\n
Solute<\/strong><\/td>\nMeasured Concentration (mg\/L)<\/strong><\/td>\nAtomic weight(g)<\/strong><\/td>\nMolarity (mmol\/L)<\/strong><\/td>\nValence (charge)<\/strong><\/td>\nmeq\/L<\/strong><\/td>\n<\/tr>\n
[latex]{Ca}_{}^{2 +}[\/latex]<\/td>\n75<\/td>\n40.08<\/td>\n<\/td>\n2<\/td>\n<\/td>\n<\/tr>\n
[latex]{Mg}_{}^{2 +}[\/latex]<\/td>\n25<\/td>\n24.31<\/td>\n<\/td>\n2<\/td>\n<\/td>\n<\/tr>\n
[latex]{Na}_{}^{+}[\/latex]<\/td>\n5.6<\/td>\n23<\/td>\n<\/td>\n1<\/td>\n<\/td>\n<\/tr>\n
[latex]K_{}^{+}[\/latex]<\/td>\n2.1<\/td>\n39.1<\/td>\n<\/td>\n1<\/td>\n<\/td>\n<\/tr>\n
[latex]{Fe(III)}_{}^{}[\/latex]<\/td>\n0.2<\/td>\n55.8<\/td>\n<\/td>\n3<\/td>\n<\/td>\n<\/tr>\n
[latex]{HCO}_{3}^{-}[\/latex]<\/td>\n109<\/td>\n61<\/td>\n<\/td>\n1<\/td>\n<\/td>\n<\/tr>\n
[latex]{SO}_{4}^{2 -}[\/latex]<\/td>\n242<\/td>\n96<\/td>\n<\/td>\n2<\/td>\n<\/td>\n<\/tr>\n
[latex]{Cl}_{}^{-}[\/latex]<\/td>\n9.3<\/td>\n35.5<\/td>\n<\/td>\n1<\/td>\n<\/td>\n<\/tr>\n
[latex]{NO}_{3}^{-}[\/latex]<\/td>\n15<\/td>\n62<\/td>\n<\/td>\n1<\/td>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
\n

Solution for Exercise 22<\/strong><\/span><\/a>\u2ba7<\/p>\n<\/div>\n

\n

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