Exercise 3 – Solution

Contour interval = (5.3 m) / (16 head drops) = 0.33125 m

$\displaystyle Q_{total}=KHw\frac{n_{f}}{n_{d}}a_{r}$

The aspect ratio is one, so a_r = 1

Q_total = (0.2 m/d) (5.3 m) (28 m) (3 flow tubes) / (16 head drops) = 5.6 m³/d

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