Solution Exercise 6

Kf = 10 m d−1, which is 1.2 × 10−4 m s−1, so with

\displaystyle K_{f}=\frac{k\rho _{f}g}{\mu _{f}}

The Rayleigh number can be calculated as

\displaystyle Ra=\frac{\Delta \rho gkH}{\mu D_{c}}=\frac{K_{f}\Delta \rho gH}{\rho _{f}D_{C}}= \displaystyle \frac{1.2\times 10^{-4}\times 25\times 9.81\times 10}{1000\times 5.0\times 10^{-10}}=5.7\times 10^{5}

Where it was assumed that D = DC = 5.0 × 10−10 m2 s−1 and the representative density values for fresh water and seawater were taken as provided in the text of this book.

Return to Exercise 6

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Variable-Density Groundwater Flow Copyright © 2022 by Vincent E.A. Post and Craig T. Simmons. All Rights Reserved.