Solution Exercise 5
Calculate the [latex]\frac{_{}^{3}H}{_{}^{3}{He}}[/latex] age using Equation (14) as shown here.
[latex]Age = \frac{\ln\left( 1 + \frac{6.8}{0.72} \right)}{\frac{ln(2)}{12.32}} = 41.7\ years[/latex]
Calculate the [latex]\frac{_{}^{3}H}{_{}^{3}{He}}[/latex] age using Equation (14) as shown here.
[latex]Age = \frac{\ln\left( 1 + \frac{6.8}{0.72} \right)}{\frac{ln(2)}{12.32}} = 41.7\ years[/latex]