Modifications to Original Release
Changes from the Original Version to Version 2
Original Version: September 18, 2023, Version 2: October 30, 2023
Page numbers refer to the original PDF.
page ii, added doi
page xi, corrected 70 to 90
page 153, Figure 87 changed the denominator from 200 to 2000 in the third expression of part a)
page 196, changed t1 = time at head h2 to t1 = time at head h1
Changes from the Version 2 to Version 3
Version 3: March, 6, 2024
Page numbers refer to the PDF of Version 2.
page iii, corrected APA citation that was missing the third author’s name
page 98, a number of changes were made:
The content of the first 3 paragraphs including table and equations were changed from the following as shown in gray:
Using the relationship f(r/B) = 1.7 = exp(r/B)K0(r/B), then from Figure 48, the value between X = 1.5 and X = 2.0. The interpolation is shown below.
|
X
|
K0(x)
|
exp (x) K0(x)
|
|---|---|---|
|
1.5
|
0.21
|
0.96
|
|
1.7
|
0.17 (interpolated)
|
0.91 (interpolated)
|
|
2.0
|
0.11
|
0.84
|
[latex]T = \frac{4250\ \frac{m^{3}}{d}\ 0.17}{2\ (3.14)\ 3.7\ m} = 31.1\frac{m^{2}}{d}[/latex]
S is then computed from Equation (53).
[latex]S = \frac{4\ \left( 31.1\frac{m^{2}}{d} \right)\ 0.011d}{2\ (75\ m)\ (44.1)} = 0.0002\ = \ 2x10^{- 4}[/latex]
to:
Using the relationship f(r/B) = 1.7 = exp(r/B)K0(r/B), then from Figure 48, the value is between exp(x)K0(x) = 1.66 and exp(x)K0(x) = 1.75. The interpolation is shown below.
| x | K0(x) | exp (x) K0(x) |
|---|---|---|
| 0.40 | 1.11 | 1.66 |
| 0.37 (interpolated) | 1.16 (interpolated) | 1.7 |
| 0.35 | 1.23 | 1.75 |
Given that x = 0.37 m, with the observation well located 75 m from the pumping well, then B = 75 m / 0.37 = 203 m. Now using Equation (52).
[latex]T = \frac{4250\ \frac{m^{3}}{d}\ 1.16}{2\ (3.14)\ 3.7\ m} = 212\frac{m^{2}}{d}[/latex]
S is then computed from Equation (53).
[latex]S = \frac{4\ \left( 212\ \frac{m^{2}}{d} \right)\ 0.011d}{2\ (75\ m)\ (203\ m)} = 0.0003\ = \ 3x10^{- 4}[/latex]
In addition the calculation of K’ was changed from the following as shown in gray:
[latex]K' = \frac{31.1\frac{m^{2}}{d}\ 15\ m}{(44.1m)^{2}} = 0.24\frac{m}{d}[/latex]
to:
[latex]K' = \frac{212\frac{m^{2}}{d}\ 15\ m}{(203\ m)^{2}} = 0.08\frac{m}{d}[/latex]
page 351, corrected format for Author’s name and title